Answer: The molarity of [tex]Br^-[/tex] anions in the chemist's solution is 0.0084 M
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in ml
moles of [tex]FeBr_3[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{0.0411g}{295.6g/mol}=0.00014mol[/tex]
Now put all the given values in the formula of molality, we get
[tex]Molarity=\frac{0.00014\times 1000}{50}=0.0028[/tex]
As 1 mole of [tex]FeBr_3[/tex] gives = 3 moles of [tex]Br^-[/tex]
0.0028 moles of [tex]FeBr_3[/tex] gives = [tex]\frac{3}{1}\times 0.0028=0.0084 moles[/tex] of [tex]Br^-[/tex]
Thus the molarity of [tex]Br^-[/tex] anions in the chemist's solution is 0.0084 M
