Answer:
The solution set of the quadratic equation is
x = {7, -5}
Step-by-step explanation:
Given the quadratic equation
[tex]$ x^2 - 2x -35 = 0 $[/tex]
We need to factor this equation
So you need two numbers such that
a + b = -2
and
a×b = -35
How about -7 and 5?
-7 + 5 = -2
-2 = -2
and
-7×5 = -35
-35 = -35
(x - 7)(x + 5) = 0
(x - 7) = 0
x = 7
and
(x + 5) = 0
x = -5
Therefore, the solution set of the quadratic equation is
x = {7, -5}
Verification:
Plug 7 into the quadratic equation
[tex]x^2 - 2x -35 = 0 \\\\(7)^2 - 2(7) -35 = 0 \\\\49 - 14 - 35 = 0 \\\\49 - 49 = 0\\\\0 = 0[/tex]
Plug -5 into the quadratic equation
[tex]x^2 - 2x -35 = 0 \\\\(-5)^2 - 2(-5) -35 = 0 \\\\25 + 10 - 35 = 0 \\\\35 - 35 = 0\\\\0 = 0[/tex]
