Complete Question
The complete question is shown on the first uploaded image
Answer:
The confidence level interval is [tex]0.016 \le C \le 0.404[/tex]
Step-by-step explanation:
The sample size is [tex]n = 20[/tex]
The number planning to increase workforce is [tex]x = 3[/tex]
The confidence level is [tex]c = 98[/tex]%
The value of proportion for a plus 4 method is
[tex]p = \frac{x+2}{n+4}[/tex]
substituting values
[tex]p = \frac{3+2}{20+4}[/tex]
[tex]p =0.21[/tex]
The z-critical value at confidence level of 98% is
[tex]z_{c}=z_{0.98} = 2.33[/tex]
This values is obtained from the standard normal table
The confidence level interval can be mathematically represented as
[tex]C =p \ \pm z_{c} * \sqrt{\frac{p(1-p)}{n+4} }[/tex]
substituting values
[tex]C = 0.21 \pm 2.33 * \sqrt{\frac{0.21(1- 0.21)}{20 +4} }[/tex]
[tex]C = 0.21 \pm 0.194[/tex]
=> [tex]0.016 \le C \le 0.404[/tex]
