Answer: a. 31.304. b. 1525. c. 1589.17
Explanation:
Lead time = 5 weeks
Standard deviation of weekly demand = 14 pints
a. ✓L × Standard deviation Weekly
= ✓5 × 14
= 2.236 × 14
= 31.304
b. Average demand during the 5-week lead time will be:
= Leadtime × weekly demand
= 5 × 305
= 1525
c. Note that the Z value at 96% service level is 2.05
R=dL+z*sd*sqrt(L)= (305 × 5)+ (2.05 × 14 × ✓5)
= 1525 + 64.17
= 1589.17