Answer:
The probability that exactly 11 of the chosen clay objects are vases
P(X = 11 ) = 0.16472
Step-by-step explanation:
Step(i):-
Given students created 19 clay objects, 12 of which were vases
probability of successes
[tex]p = \frac{x}{n} = \frac{12}{19} = 0.6315[/tex]
q = 1 - p = 1 - 0.6315 = 0.3685
Step(ii):-
Given n = 16
Let 'X' be the random variable in binomial distribution
[tex]P(X = r) = n _{C_{r} } p^{r} q^{n-r}[/tex]
The probability that exactly 11 of the chosen clay objects are vases
[tex]P(X = 11) = 16 _{C_{11} } (0.6315)^{11} (0.3585)^{16-11}[/tex]
we will use formula
[tex]n_{C_{r} } = \frac{n!}{(n-r)!r!}[/tex]
[tex]n_{C_{r} } =n_{C_{n-r} }[/tex]
[tex]16_{C_{11} } =16_{C_{16-11} }= 16_{C_{5} } = \frac{16 X 15 X 14 X 13 X 12}{5 X 4 X 3 X 2 X 1} = 4368[/tex]
[tex]P(X = 11) = 4368 (0.006369)(0.005921)[/tex]
P(X = 11 ) = 0.16472
Conclusion:-
The probability that exactly 11 of the chosen clay objects are vases
P(X = 11 ) = 0.16472