Answer:
[tex]2n\sqrt{n}[/tex]
Step-by-step explanation:
If I were not wrong, the expression is
[tex]$\frac{1}{3} \sqrt{18n^2} \cdot \sqrt{2n} $[/tex]
First, state that [tex]18 = 3 \cdot 3 \cdot 2[/tex], so,
[tex]$\frac{1}{3} \sqrt{3^2 \cdot 2n^2} \cdot \sqrt{2n} $[/tex]
[tex]$\frac{1}{3} \cdot 3n\sqrt{2} \cdot \sqrt{2n} $[/tex]
[tex]$n\sqrt{2} \cdot \sqrt{2n} $[/tex]
[tex]n\sqrt{2 \cdot 2n}[/tex]
[tex]n\sqrt{2^2n}[/tex]
[tex]2n\sqrt{n}[/tex]
