Find the volume of a pyramid with a square base where the perimeter of the base is 12.8m. and the height of the pyramid is 12.5m. round your answer to the nearest tenth of a cubic meter

Respuesta :

Answer:

[tex]V=42.7m^3[/tex]

Step-by-step explanation:

The volume of a square pyramid is given by the equation:

[tex]V=\frac{A_{b}h}{3}[/tex]

where [tex]A_b[/tex] is the area of the base, in this case the area of the square. And h is the height of the pyramid:

[tex]h=12.5m[/tex]

To find the area of the square we need the length of its sides, which can be found dividing the perimeter by four.

The perimeter is:

[tex]p=12.8m[/tex]

thus, the length of the side is:

[tex]l=\frac{p}{4} =\frac{12.8m}{4}=3.2m[/tex]

and the area of square at the base is then given by the formula:

[tex]A_b=l^2\\\\A_b=(3.2m)^2\\\\A_b=10.24m^2[/tex]

Finally we substitute all the known values into the equation for the volume:

[tex]V=\frac{A_{b}h}{3}[/tex]

[tex]V=\frac{(10.24m^2)(12.5m)}{3}\\ \\V=\frac{128m^3}{3}\\ \\V=42.667m^3[/tex]

rounding the volume to the nearest tenth of a cubic meter:

[tex]V=42.7m^3[/tex]

Answer: 58.0266667=58.0m^3