Step-by-step explanation:
The function is as follows :
[tex]f(x) = x^2 + 5x + 5[/tex]
We need to find the zeroes of the function in the simplest radical form.The zero of the above function is given by :
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}[/tex]
Here,
b = 5
a = 1
c = 5
So,
[tex]x=\dfrac{-5\pm \sqrt{5^2-4\times 1\times 5} }{2(1)}\\\\x=\dfrac{-5\pm \sqrt{25-20} }{2(1)}\\\\x=\dfrac{-5\pm \sqrt{5} }{2}[/tex]
Hence, the correct option is (c).
