Triangle ABC is a right triangle. If AC =7 and BC=8, find AB . Leave your answer in simplest radical form.
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Answer:
AC=[tex]\sqrt{15\\[/tex]
Step-by-step explanation:
AC is the base, BC is the hypotenuse, so the side length is AB.
We are given that AC=7 units, and BC is equal to 8.
Thus we have 8^2-7^2=(AB)^2
64-49=(AC)^2
15=(AC)^2
AC=[tex]\sqrt{15\\[/tex]
The required length of the AB = √15.
Triangle ABC is a right triangle. If AC =7 and BC=8, AB is to be determined.
In a right-angled triangle, its side, such as hypotenuse, perpendicular and base is Pythagorean triplets.
⇒ Pythagorean theorem for Triangle ABC
⇒BC² = AB²+AC²
⇒ 8² = AB² + 7²
⇒ AC² = 64 - 49
⇒ AC = √15
Thus, the required length of the AB = √15.
Learn more about Pythagorean triplets here:
brainly.com/question/22160915
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