sakurablxssom
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Please help! Correct answer only, please! I've been stuck on this assignment since yesterday, and I don't want to lose any more points.

Trudy has a collection of 11 dice, 4 of which have twelve sides.
If Trudy randomly rolls 4 dice in a specific order, what is the probability that just the first 2 of the chosen dice have twelve sides?

Write your answer as a decimal rounded to four decimal places.

Respuesta :

Answer:

Approximately 0.0364

Idk if this is right... :(

Step-by-step explanation:

4 dice with 12 sides

7 dice without 121 sides.

There is a [tex]\frac{4}{11}[/tex] chance that the first dice has 12 sides.

There is a [tex]\frac{3}{10}[/tex] chance that the second dice has 12 sides.

There is a [tex]\frac{7}{9}[/tex] chance that the third dice doesn't have 12 sides.

There is a [tex]\frac{3}{4}[/tex] chance that the fourth dice doesn't have 12 sides.

Multiply them up:

[tex]\frac{4}{11}*\frac{3}{10}*\frac{7}{9}*\frac{3}{4}=\frac{252}{3960}=0.0363636363636...[/tex]

So approximately 0.0364