If a triangle has an area of 108 mm2 and the base of the triangle is 18 mm, what is the height of the triangle? PLEASE HELP ME

Respuesta :

Answer:12

Step-by-step explanation:

Area=1/2base xheight

(108×2)÷18

12

Hi1315

Answer:

[tex]height = 12 \: \: mm[/tex]

Step-by-step explanation:

[tex]area = \frac{1}{2} \times height \times base \\ 108 = \frac{1}{2} \times h \times 18 \\ 108 = \frac{18h}{2} \\ 108 = 9h \\ \frac{108}{9} = \frac{9h}{9} \\ h = 12[/tex]

hope this helps

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