Answer:
Option A.
Step-by-step explanation:
It is given that the smallest of 6 consecutive integers is p. So, all numbers are
[tex]p,p+1,p+2,p+3,p+4,p+5[/tex]
The greatest is q.
[tex]q=p+5[/tex]
Now, the value of the average of p and q in terms of p is
[tex]Average=\dfrac{p+q}{2}[/tex]
[tex]Average=\dfrac{p+p+5}{2}[/tex]
[tex]Average=\dfrac{2p+5}{2}[/tex]
[tex]Average=\dfrac{2p}{2}+\dfrac{5}{2}[/tex]
[tex]Average=p+2.5[/tex]
Therefore, the correct option is A.
