Answer:
39,070,080 possible passwords
Step-by-step explanation:
The complete alphabet has 26 letters. Removing the 5 vowels, we have 21 letters.
We want to make groups of 6 letters, and the order of each letter matters, because it will create a different password, so we can write a permutation to solve this problem.
The number of elements is 21, and the group has 6 elements, so we have a permutation of 21 choose 6:
P(21,6) = 21! / (21-6)! = 21! / 15! = 21 * 20 * 19 * 18 * 17 * 16 = 39,070,080 possible passwords
