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Maryann is tracking the change in her vertical jump over 6 months. Use the table to write a linear function that models her jump distance.


Month Vertical Jump in inches
0 16
2 17
4 18
6 19
f of x equals one half times x plus 16
f of x equals one half times x plus 19
f(x) = 2x + 16
f(x) = 2x + 19

Respuesta :

Answer:

A linear function that models her jump distance is [tex]f(x)=\frac{1}{2}x+16[/tex]

Step-by-step explanation:

Month        Vertical Jump in inches

0                          16

2                          17

4                          18

6                          19

We are supposed to find a linear function that models her jump distance.

Two point slope form : [tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex](x_1,y_1)=(0,16)\\(x_2,y_2)=(2,17)[/tex]

Substitute the values in the formula :

[tex]y-16=\frac{17-16}{2-0}(x-0)\\y-16=\frac{1}{2}x\\y=\frac{1}{2}x+16[/tex]

So,[tex]f(x)=\frac{1}{2}x+16[/tex]

So, Option A is true

Hence a linear function that models her jump distance is [tex]f(x)=\frac{1}{2}x+16[/tex]

oct3621

Answer:

the answer is A

Step-by-step explanation:

i got it right on the test, flvs.

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