Respuesta :
Answer:
[tex]x=-2,1,3[/tex]
Step-by-step explanation:
Given: The curved line represented by the function [tex]f(x)[/tex] crosses the x-axis at [tex](-2,0),(1,0),(3,0)[/tex] and y-axis at [tex](0,-6)[/tex]
To find: value of x for which [tex]f(x)=0[/tex]
Solution:
[tex]f(x)=0[/tex] gives those values of x for which the curve represented by the given function cuts the x-axis.
According to question, the curve cuts the x-axis at [tex]x=-2,1,3[/tex]
The values of x, when f(x) = 0 are the y-intercepts of the graph, and the values are -2, 1 and 3
The points on the function on the graph are given as:
[tex](x,y) = \{(-2,0), (1,0), (3,0), (0,-6)\}[/tex]
In the above ordered pairs, the points where y or f(x) equals 0 are:
[tex](x,y) = \{(-2,0), (1,0), (3,0)\}[/tex]
Remove the y-values
[tex]x = \{-2, 1, 3\}[/tex]
The above set represents the values of x, when f(x) = 0.
Hence, the values of x, when f(x) = 0 are -2, 1 and 3
Read more about y-intercepts at:
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