The function f(x) is shown on the graph.

On a coordinate plane, a curved line with 3 arcs, labeled f of x, crosses the x-axis at (negative 2, 0), (1, 0), and (3, 0), and the y-axis at (0, negative 6).

If f(x) = 0, what is x?

Respuesta :

Answer:

[tex]x=-2,1,3[/tex]

Step-by-step explanation:

Given: The curved line represented by the function [tex]f(x)[/tex] crosses the x-axis at [tex](-2,0),(1,0),(3,0)[/tex] and y-axis at [tex](0,-6)[/tex]

To find: value of x for which [tex]f(x)=0[/tex]

Solution:

[tex]f(x)=0[/tex] gives those values of x for which the curve represented by the given function cuts the x-axis.

According to question, the curve cuts the x-axis at [tex]x=-2,1,3[/tex]

The values of x, when f(x) = 0 are the y-intercepts of the graph, and the values are -2, 1 and 3

The points on the function on the graph are given as:

[tex](x,y) = \{(-2,0), (1,0), (3,0), (0,-6)\}[/tex]

In the above ordered pairs, the points where y or f(x) equals 0 are:

[tex](x,y) = \{(-2,0), (1,0), (3,0)\}[/tex]

Remove the y-values

[tex]x = \{-2, 1, 3\}[/tex]

The above set represents the values of x, when f(x) = 0.

Hence, the values of x, when f(x) = 0 are -2, 1 and 3

Read more about y-intercepts at:

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