Answer:
First Box: Factor by difference of squares
Second Box: It has all perfect squares
Third Box: see my work
Step-by-step explanation:
We have the equation [tex]4x^2=36[/tex]
Before we do anything, let us bring all of the terms to the left side
[tex]4x^2-36=0[/tex]
Now that we have moved the terms to one side, it is clear that we have a difference of squares.
-Work-
[tex]4x^2=36\\\\4x^2-36=0\\\\(2x+6)(2x-6)=0\\\\[/tex]
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[tex]2x+6=0\\\\2x=-6\\\\x=-3[/tex]
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[tex]2x-6=0\\\\2x=6\\\\x=3[/tex]
