Answer:
8
There are two real solutions
Step-by-step explanation:
We have the following quadratic equation
[tex]2x^2+4x+1=0[/tex]
a refers to the coefficient next to [tex]x^2[/tex]
b refers to the coefficient with [tex]x[/tex]
c refers to the number without x
This means that
[tex]a=2\\b=4\\c=1[/tex]
We now can plug these variables into the discriminant formula
[tex]b^2-4ac\\\\(4)^2-4(2)(1)\\\\16-8\\\\8[/tex]
As our answer is positive, we can determine that this quadratic equation has two real solutions.
