abdullayevaalbina97 abdullayevaalbina97

13-06-2020
Physics

contestada

A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?
A) 152 m
B) 160 m
C) 184 m
D) 318 m

Respuesta :

ivoryjwalters ivoryjwalters

13-06-2020

Answer:

Explanation: The initial velocity has two component v x and v y. The initial velocity in direction of y is given.

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maxwellekoh maxwellekoh

13-06-2020

Answer:

D

Explanation:

The range is how far the projectile can go;

R = U^2sin2A/g

Where U is the initial velocity

A is the angle of inclination

=60^2sin2(30)/10 = 3600 sin60 / 10

= 311.8m

The exact answer should 312m

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