Question Correction
Let A and B be two finite set such that n(A) = 20 , n(B) = 28 and n(AUB)=35, Find [tex]n(A \cap B)[/tex]
Answer:
[tex]n(A \cap B)=13[/tex]
Step-by-step explanation:
Given two finite sets such that:
[tex]n(A) = 20\\n(B) = 28\\n (A \cup B) = 35[/tex]
We are to determine [tex]n(A \cap B)[/tex].
Now, by set theory
[tex]n (A \cup B)=n(A)+n(B)-n(A \cap B)\\35=20+28-n(A \cap B)\\35=48-n(A \cap B)\\n(A \cap B)=48-35\\n(A \cap B)=13[/tex]
