In the given the figure above, m∠BAC = 64° and m∠CBA = 56°. Part I: Find the m∠DEC. Part II: Explain the steps you took to arrive at your answer. Make sure to justify your answer by identifying any theorems, postulates, or definitions used.

In the given the figure above mBAC 64 and mCBA 56 Part I Find the mDEC Part II Explain the steps you took to arrive at your answer Make sure to justify your ans class=

Respuesta :

Answer:

56, see step-by-step.

Step-by-step explanation:

1. AB is parallel to CD.                                1. Given

  BC is parallel to DE.

  m<BAC=64 and m<CBA =56

2. m<BAC + m<CBA + m<BCA =180       2. The angles in a triangle add up to       180

3. 64+ 56+ m<BCA=180 3. Substitution property of equality.

4. 120 + m<BCA=180 4. Addition property of equality.

5. m<BCA=60 5. Subtraction property of equality.

6. BC is a transversal that cuts through parallel lines AB and CD.

6. Def. of transversal.

7. m<CBA = m<BCD 7. If two parallel lines are cut by a transversal, then alternate interior angles are congruent.

8. m<BCA+m>BCD+m<DCE= 180. 8. Angle addition postulate

9. 60+56+m<DCE=180. 9.substitution.

10. 116 + m<DCE =180 10. Addition property of equality.

11. M<DCE =64 11. Subtraction property of equality.

12. DC is a transversal that cuts through parallel line BC and DE.

12. Def of transversal.

13. m<EDC= m<BCD 13. If two parallel lines are cut by a transversal, then alternate interior angles are congruent.

14. m<EDC= 60. 14. Substitution property of equality.

15. m<EDC+m<DCE+m<Dec=180. 15. Angle addition postulate

16. 56+64+m<dec = 180.16 Substitution property of equality.

17. 120+ m<dec = 180. Addition property of equality.

18. m<dec = 60 18. Subtraction property of equality.