Answer:
The correct option is C
Explanation:
From the question we are told that
The distance between axles of the car is [tex]d_a = 6.2[/tex]
The position of the car's center of mass is [tex]D = 2.2 \ m \ in \ front \ of \ the \ axel[/tex]
Now we can evaluate the distance of the center of mass to the rear axle as follows
[tex]k = d_a - D[/tex]
substituting values
[tex]k = 6.2 - 2.2[/tex]
[tex]k = 4 \ m[/tex]
assuming the car is at equilibrium, taking moment about the center of mass
[tex]W_{front \ axle} * D - W_{rear \ axle} * k = 0[/tex]
=> [tex]W_{front \ axle} * D = W_{rear \ axle} * k[/tex]
=> [tex]\frac{W_{front \ axle}}{W_{rear \ axle} } = \frac{k}{D}[/tex]
substituting values
[tex]\frac{W_{front \ axle}}{W_{rear \ axle} } = \frac{4}{2.2}[/tex]
[tex]\frac{W_{front \ axle}}{W_{rear \ axle} } = 1.81[/tex] Note [[tex]W_{front \ axle}[/tex] is the front axle weight and
[tex]W_{rear \ axle}[/tex] is the rear axle weight ]
