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A bucket containing 40 red balls, 25 black balls, and 35 white balls is used in a probability experiment. Each trial consists of mixing the balls and drawing one at random, replacing it and mixing again, and drawing a new ball at random. The new ball is then replaced so that another trial can be performed. One hundred trials are performed in all. The number of trials in which the first ball is red and the second ball is black is most likely to be:__________.
A. 8
B. 10
C. 12
D. 14

Respuesta :

freddiemarchant

Answer:B

Step-by-step explanation:0.4 times 0.25=0.1

1/0.1= 10

Answer:

B. 10.

Step-by-step explanation:

The probability of drawing a red ball = 40/100   = 0.4.

The probability of drawing a black ball = 25/100 = 0.25.

Probability(Drawing a red then a black ball) = 0.4 + 0.25 = 0.1.

So in 100 draws we would expect 0.10 * 100 = 10 times for this to occur.

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