Answer:
Mean = 3.12, Variance = 3.324, Standard deviation = 1.8232
Step-by-step explanation:
Total number of students = 10 students.
Given data, 1.1, 5.2, 3.6, 5.0, 4.8, 1.8, 2.2, 5.2, 1.5, 0.8
To find the mean, at first we have to take the sum of all given data and then divide with the number of students.
Let the data is X, = 1.1, + 5.2, + 3.6, + 5.0, + 4.8, + 1.8, + 2.2, + 5.2, + 1.5, + 0.8 = 31.2
Mean = 31.2 / 10 = 3.12
[tex]\text{Standard deviation, S} = \sqrt{\frac{\sum x^{2} - \left [ (\sum x)^{2}/n \right ]}{n-1}} \\S = 1.8232 \\\rm The \ Variance = S^{2} = 3.324[/tex]
