Answer:
Option D:
The volume of the larger can is [tex]229.12 in ^3[/tex]
Step-by-step explanation:
We know that if two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube.
Let:
z-----> the scale factor
x-----> the volume of the larger can
y-----> the volume of the smaller can
so
[tex]z^3=\frac{x}{y}[/tex]
In this problem we have:
[tex]z=2[/tex]
[tex]y=28.64 in^3[/tex]
Substitute and solve for x.
[tex]2^3=\frac{x}{28.64}[/tex]
[tex]x=2^3*28.64=229.12^3[/tex]
Therefore, the answer is [tex]229.12 in ^3[/tex].
Hope this helps! (brainliest?)
