Answer:
2.07 x 10¹¹Nm²/C
Explanation:
From Gauss's law, the flux (∅) through a closed surface is given by ;
∅ = [tex]\frac{Q_{en}}{e_0}[/tex]
Where;
[tex]Q_{en}[/tex] = enclosed charge within the closed surface
[tex]e_0[/tex] = permittivity of free space = 8.85 x 10⁻¹² Nm²/C²
But from the question, we can assume that the closed surface is a cube having 6 square sides of length 40cm.
Therefore, the flux through the square is given by;
∅ₓ = [tex]\frac{1}{6} \frac{Q_{en}}{e_0}[/tex] -----------------(i)
[tex]Q_{en}[/tex] = 11C
Substitute the values of [tex]Q_{en}[/tex] and [tex]e_0[/tex] into equation (i) as follows;
∅ₓ = [tex]\frac{1}{6} \frac{11}{8.85*10^{-12}}[/tex]
∅ₓ = 0.207 x 10¹²Nm²/C
Therefore, the flux through the square is 2.07 x 10¹¹Nm²/C
