Answer:
The absolute value function that models the path of the ball is
[tex]f(x) = \left | -\frac{3}{4}\cdot x + 15 \right |[/tex]
The coordinates when the ball passes within 3 meters of the wall is [tex]\left (3, 12\tfrac{3}{4} \right )[/tex]
Step-by-step explanation:
Given that the ball rolls without other external influences, we have;
(y - 0) = (x - 15)
The slope, m is give by the relation;
m = (y₂ - y₁)/(x₂ - x₁)
m = (15 - 0)/(0-20) = -3/4
The equation of the path of the ball in slope and intercept form is presented as follows;
y = m·x + c
15 = -3/4 ×0 + c = 15
c = 15
The absolute value function that models the path of the ball is then;
[tex]f(x) = \left | -\frac{3}{4}\cdot x + 15 \right |[/tex]
The vale of the function when x = 3 is given by the relation
[tex]f(x) = \left | -\dfrac{3}{4}\times 3 + 15 \right | = \dfrac{51}{4}[/tex]
Therefore, we have the coordinates as [tex]\left (3, 12\tfrac{3}{4} \right )[/tex].
