makayla0919
contestada

please help me fast
When iron rusts in air, iron(III) oxide is produced. How many moles of oxygen react with 80.9 mol of iron in the
rusting reaction?
4Fe(s) + 302(g) → 2Fe2O3(s)
Select one:
O a. 60.7
O b. 108
O c. 80.9
O d. 121

Respuesta :

Answer:

60.7 mole

Explanation:

for every 4 moles of iron 3 moles of oxygen is used.

So, moles of oxygen = [tex]\frac{3 * 80.9}{4}[/tex] = 60.675
the answer is going to be A. 60.7 hope you have a good day

Otras preguntas