In AABC, AB = 3 and AC = 9. Find m28 to the nearest degree.
52
58
72
18
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Answer:
72°
Step-by-step explanation:
==>Given:
∆ABC
AB = Opposite side length = 9
AC = Adjacent side length = 3
==>Required:
The measure of angle B
==>Solution:
Since ∆ABC is a right angled triangle, and we are given two sides (opposite and adjacent sides), to find m<B, we'd use the trigonometry formula tan B = Opposite/Adjacent.
Thus,
tan B = 9/3
tan B = 3
B = tan^-1(3) = 71.5650512°
<B to the nearest degree ≈ 72°