Answer:
The person is running at a speed of 2.564 m/s
Explanation:
Given;
mechanical energy dissipated per kilogram per step, E/kg/S = 0.6 J/kg/S
mass of the person, m = 52 kg
power developed by the person, P = 80 W
mechanical energy of the person per step, E = 0.6 J/kg x 52 kg
[tex]E_{step}[/tex] = 31.2 J
mechanical energy for the total step, [tex]E_{total}[/tex] = 31.2 J x S
P = E / t
[tex]P_{avg} = \frac{E_{total}}{t} \\\\P_{avg} = \frac{E_{step}*S}{t}\\\\\frac{P_{avg}}{E_{step}} = \frac{S}{t} \\\\\frac{S}{t} = \frac{80}{31.2} \\\\\frac{S}{t} = 2.564 \ m/s[/tex]
Therefore, the person is running at a speed of 2.564 m/s
