Answer:
0.226 mol/L
Explanation:
The following data were obtained from the question:
Volume = 14.17 mL
Mass of sodium sulphate, Na2SO4 = 453.76 mg
Molarity =..?
Next, we shall determine the number of mole in 453.76 mg of Na2SO4. This is illustrated below:
Molar mass of Na2SO4 = (2x23) + 32 +(16x4) = 142g/mol
Mass of Na2SO4 = 453.76 mg = 453.76×10¯³ g
Mole of Na2SO4 =..?
Mole = mass /Molar mass
Mole of Na2SO4 = 453.76×10¯³ / 142
Mole of Na2SO4 = 3.20×10¯³ mole
Finally, we shall determine the molarity of Na2SO4 solution as follow:
Mole of Na2SO4 = 3.20×10¯³ mole
Volume = 14.17 mL = 14.17/1000 = 1.417×10¯² L
Molarity =?
Molarity = mole /Volume
Molarity = 3.20×10¯³ / 1.417×10¯²
Molarity = 0.226 mol/L
Therefore, the molarity of the sodium sulphate, Na2SO4 solution is 0.226 mol/L
