Answer:
52.78% probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.
Step-by-step explanation:
An uniform probability is a case of probability in which each outcome is equally as likely.
For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.
The probability that we find a value X greater than x is given by the following formula.
[tex]P(X > x) = \frac{b-x}{b-a}[/tex]
Uniformly distributed between 0 and 9 minutes.
This means that [tex]a = 0, b = 9[/tex]
Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.
[tex]P(X > 4.25) = \frac{9 - 4.25}{9 - 0} = 0.5278[/tex]
52.78% probability that a randomly selected passenger has a waiting time greater than 4.25 minutes.
