The linear equation of the line is y = -1/5x - 3 and y + 3 = -1/5(x - 0)
How to determine the line equation?
The slope is given as:
m = -1/5
The y-intercept is given as:
c = -3
A linear equation in slope intercept form is represented as:
y = mx + c
So, we have:
y = -1/5x - 3
The equation in point slope form is calculated as follows:
y = -1/5x - 3
Add 3 to both sides
y + 3 = -1/5x
Express -1/5x as -1/5(x)
y + 3 = -1/5(x)
Subtract 0 from x
y + 3 = -1/5(x - 0)
Hence, the linear equation of the line is y = -1/5x - 3 and y + 3 = -1/5(x - 0)
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