Hi1315
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ABCD is a parallelogram​.
Given that,
DC = CE
prove that,
area of the ADE triangle is equal to the area of the parallelogram​.


need explanation

plzz help!!
will give the brainliest!!​

ABCD is a parallelogramGiven thatDC CE prove thatarea of the ADE triangle is equal to the area of the parallelogramneed explanationplzz helpwill give the brainl class=

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bekkarmahdi702

Answer:

Step-by-step explanation:

We khow that ABCD is a parallelogram so its area is the product of the base (DC) and the the height

  • Let H be the height of the paralellogram and A its area
  • So A= DC*H

ADE is a triangle . Its area is the product of the height and the base(DE) over 2

  • We notice that the paralellogram and the triangle have both the same height
  • Let S be the area of the triangle
  • S= (DE*H)/2= DE/2 *H = DC *H

So the triangle and the parallelogram have the same area

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