Answer and Explanation:
The computation is shown below:
For determining each part first we have to do the following calculations
Critical value of t = 3.250
Null hypothesis = 1.5
Alternative hypothesis ≠ 1.5
Population mean [tex]\mu[/tex] = 1.5
Sample mean [tex]\bar X[/tex]= 1.30
Sample size [tex]n[/tex] = 10.00
Sample standard deviation [tex]s[/tex] = 0.900
Standard error of mean is
[tex]s_x = \frac{s}{\sqrt{n} }[/tex]
[tex]= \frac{0.900}{\sqrt{10.00}}[/tex]
= 0.2846
Test static is
[tex]t = \frac{x - \mu}{s_x}[/tex]
[tex]= \frac{1.30 - 1.5}{0.2846}[/tex]
= -0.703
a. The null hypothesis is
μ = 1.5
Alternate Hypothesis is
μ ≠ 1.5
b. reject [tex]H_o[/tex] if t is not between
-3.250 and 3.250
c. The value of the test statistic is
t = -0.703
(as we have computed above)
d. fail to reject [tex]H_o[/tex] as this data does not contradict the publisher claim
