The cylindrical can that contains more stew is the first can which has a diameter of 8 inches and a height of 4 inches.
What is the volume of a right circular cylinder?
Suppose that the radius of considered right circular cylinder be 'r' units.
And let its height be 'h' units.
Then, its volume is given as:
[tex]V = \pi r^2 h \: \rm unit^3[/tex]
Right circular cylinder is the cylinder in which the line joining center of top circle of the cylinder to the center of the base circle of the cylinder is perpendicular to the surface of its base, and to the top.
The more volume of a can is, the more stew it can store.
For first can:
- Height = 4 inches, diameter of base = 8 inches.
Since radius = diameter/2, so radius of base = 8/2 = 4 inches.
Thus, volume of first can: [tex]V = \pi (4)^2 (4) = 64\pi \: \rm unit^3[/tex]
For second can:
- Height = 7 inches, diameter of base = 6 inches.
Since radius = diameter/2, so radius of base = 6/2 = 3 inches.
Thus, volume of first can: [tex]V = \pi (3)^2 (7) = 63\pi \: \rm unit^3[/tex]
Thus, as π > 0, so first can can contain more stew.
Thus, the cylindrical can that contains more stew is the first can which has a diameter of 8 inches and a height of 4 inches.
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