Answer:
30.96 [tex]in^2[/tex]
Step-by-step explanation:
Given that
Side of square = 12 in
Diameter of circle = 12 in
We know that, radius is half of diameter,
So, r = 6 cm
We have to find the area of square which is not covered by the circle.
i.e. Required Area = Area of Square - Area of Circle
Please refer to the attached to have a better understanding of the given situation.
Formula:
Area of square = [tex](side)^2[/tex]
Area of circle = [tex]\pi r^2[/tex]
Required Area = [tex]12^2[/tex] - [tex]\pi \times 6^{2}[/tex]
[tex]\Rightarrow 144 - 3.14 \times 36\\\Rightarrow 144 - 113.04\\\Rightarrow 30.96\ in^2[/tex]
So, the answer is 30.96 [tex]in^2[/tex].
