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The number of diseased cells, d(t), remaining in a recovering patient's bloodstream t days after starting medication is given by the function below.(see image)

What is the average decrease per day in the number of cells in the patient's bloodstream from the 10th day to the 18th day?

A. 99.29 cells per day

B. 139.39 cells per day

C. 158.43 cells per day

D. 49.65 cells per day​

The number of diseased cells dt remaining in a recovering patients bloodstream t days after starting medication is given by the function belowsee imageWhat is t class=

Respuesta :

Answer:

The correct option is:

Average decrease per day = 49.65

Step-by-step explanation:

We have been given the formula to calculate the number of cell for each day:

d(t) = 2000(0.9)^t

Lets calculate the number of cells on 10th days

d(10) = 2000(0.9^10)

d(10) = 697.357

Lets calculate the number of cell on 18th day.

d(18) = 2000(0.9^18)

d(18) = 300.19

Total increase of days = 18 - 10 = 8

Totat decrease of cells = 697.357 - 300.19 = 397.167

Average decrease per day = 397.167/8

Average decrease per day = 49.65

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