Answer:
mass of CaCl₂ = 67.4 g of CaCl₂
Explanation:
A 45% CaCl₂ Solution contains 45 g of solute per 100 mL of solution.
mass concentration = mass of solute (g)/ volume of solution (L)
100 mL of solution = 100 * 1L /1000 = 0.1 L
Mass concentration of solution = 45 g/0.1 L = 450 g/L
Molar concentration of solution = mass concentration / molar mass
molar mass of CaCl₂ = 111 g/mol
molar concentration = 450 g/L / 111 g/mol = 4. 05 mol/L
Number of moles of CaCl₂ present in 150 ml of 4.05 mol/L solution = molar concentration * volume (L)
number of moles of CaCl₂ = 4.05 * 150 * 1 L/1000 = 0.6075 moles
mass of CaCl₂ present in 0.6075 moles = number of moles * molar mass
mass of CaCl₂ = 0.6075 * 111 = 67.4 g of CaCl₂
