Answer:
1. studied: range-21
interquartile-10
did not: range-46
interquartile-19.5
2.The people who studied got closer grades to each other. This shows that those who didn't study had more variation in grades. So there if you don't study you have a bigger chance of failing than studying.
For the data set of studied students:
Range = 21
Interquartile Range = 10
For the data set of numbers of students who did not studied:
Range = 46
Interquartile range = 19.5
We can conclude from that the numbers of studied students are more clustered than the numbers of the students who did not studied.
Interquartile range is the difference between the third quartile and first quartile of a data set.
In this problem,
number of students who are studied are in ascending order,
79,83,84,88,89,89,91,92,93,94,95,95,96,99,100,100,100,100
Lower data set = 79
Highest data set = 100
Range = 100-79 = 21
Total number of observation is 18
dividing the data set in two parts in 9 observations we get,
lower part is,
79,83,84,88,89,91,92,93,94
First quartile = Median of this data set = 5 th value = 89
Upper part is,
95,95,95,96,99,100,100,100,100
Third quartile = Median of upper set = 5 th value = 99
Interquartile range = 99 -89 =10
For the set of students who did not studied in ascending order:
45,58,65,72,73,77,82,83,87,89,90,91
Total number of observation = 12
Lower data set = 45
Highest data set = 91
Range = 91-45 = 46
Dividing in equal parts of 6 onservations we get,
Lower part is,
45,58,65,72,73,77
First quartile = Median of this data set = average of 3rd and 4th values [tex]=\frac{65+72}{2}=\frac{137}{2}=68.5[/tex]
Upper part is,
82,83,87,89,90,91
Third quartile = Median of this data set = average of 3rd and 4th values [tex]=\frac{87+89}{2}=\frac{176}{2}=88[/tex]
Interquartile range = 88-68.5 = 19.5
We can conclude from that the numbers of studied students are more clustered than the numbers of the students who did not studied.
Learn more about Interquartile Range here -
https://brainly.com/question/447161
#SPJ2
