Answer:
-3
Solution,
[tex] \frac{24 {x}^{2} + 25x - 47}{ax - 2} = - 8x - 3 - \frac{53}{ax - 2} \\ \frac{24 {x}^{2} + 25x - 47 }{ax - 2} = \frac{( - 8x - 3)(ax - 2) - 53}{ax - 2} \\ 24 {x}^{2} + 25x - 47 = - 8a {x}^{2} + (16 - 3a)x - 47 \\ [/tex]
Equating coefficients from both side:
[tex] - 8a = 24 \\ a = \frac{ 24}{ - 8} \\ a = - 3[/tex]
Hope this helps..
good luck on your assignment..
