Answer:
Therefore, the coordinates of point Q is (2,3)
Step-by-step explanation:
Let the coordinates of Q be(a,b)
Let R be the midpoint of PQ
Coordinates of R [tex]=(\frac{4+a}{2}, \frac{3+b}{2})[/tex]
R lies on the line x + y - 6= 0, therefore:
[tex]\implies \dfrac{4+a}{2}+ \dfrac{3+b}{2}-6=0\\\implies 4+a+3+b-12=0\\\implies a+b-5=0\\\implies a+b=5[/tex]
Slope of AR X Slope of PQ = -1
[tex]-1 \times \dfrac{b-3}{a-4}=-1\\b-3=a-4\\a-b=-3+4\\a-b=-1[/tex]
Solving simultaneously
a+b=5
a-b=-1
2a=4
a=2
b=3
Therefore, the coordinates of point Q is (2,3)
