The holding tanks are congruent. Each is in the shape of a cylinder that has been cut in half vertically. The bottom of each tank is a curved surface and the top of the pool is a flat surface. What is the volume of both tanks if the radius of tank #1 is 35 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit.

Respuesta :

Answer:

Volume of tank = 461,814 ft³

Step-by-step explanation:

Congruent tanks implies that both tanks are of identifical shape, form & dimensions. Congruent means that the tanks have the same radius as well as height. Hence, the heights and radii of tanks #1 and #2 are equal and the same.

Let's list out the information given us:

radius(tank #1) = 35 ft ⇒ radius(tank #2) = 35 ft, height(tank #2) = 120 ft ⇒ height(tank #2) = 120 ft

Volume of cylinder = πr²h

The tanks have been cut into half, as such:

Volume of tank = ½πr²h

Volume of tank = Volume(tank #1) + Volume(tank #2)

Since the tanks are congruent (same dimensions), we have:

⇒ ½πr²h + ½πr²h ⇒ πr²h

Volume of tank =  π * 35² * 120 = 147,000 π

Volume of tank = 461,814 ft³

The two holding tanks can be taken as one tank split halfway into two.

  • The volume of both tanks combined, is approximately 461814.12 cubic feet.

Reasons:

Known parameters:

The given parameters are;

The shape of the bottom = A curve

Number of holding tanks = 2

The characteristics of the tanks = Congruent tanks

Dimension of tank #1 = Dimension of tank #2

The shape of each  tank = Half cylinder

Radius of tank #1, r = 35 feet

Height of tank #2, h = 120 feet

Solution:

Given that the tanks are congruent and that each tank is a half cylinder, we have;

Sum of the volume of the tanks = Volume of tank having the radius of one of the tanks and the height of the other tank.

Sum of the volume of the tanks, V = π·r²·h

∴ V = π × 35² × 120 = 147,000·π ≈ 461814.12

The volume of both tanks, V ≈ 461814.12 ft.³

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