PLEASE HELP WITH GEOMETRY HOMEWORK!! WILL GIVE BRAINLIEST ANSWER TO THE PERSON WHO CAN GIVE ME A ANSWER WILL ALL THE WORK SHOWN TO PROVE THEIR ANSWER!!

Information needed to solve:
- Points O and P are the midpoints to the two circles
- The length between O and P is 6
-The two circles are of the same size
-DONT ASSUME ANYTHING OTHER THAN THE INFORMATION GIVEN UNLESS YOU HAVE PROOF AND EVIDENCE TO SHOW IT IS TRUE!!

PLEASE HELP WITH GEOMETRY HOMEWORK WILL GIVE BRAINLIEST ANSWER TO THE PERSON WHO CAN GIVE ME A ANSWER WILL ALL THE WORK SHOWN TO PROVE THEIR ANSWER Information class=

Respuesta :

Answer:

Shaded area = 6^2 * ( pi/3 - sqrt(3)/2 )

= 6.52 square units (to 2 places of decimals)

Step-by-step explanation:

see solution by same author given in

https://brainly.com/question/17023327?answeringSource=feedPersonal%2FhomePage%2F2

(question 17023327)

Please refer to the diagram for additional letters and measures.

Let

r=radius (OA and PA) of each circle

Area of sector PAOB

= (60+60)/360 * pi * r^2

=pi*(r^2)/3

Area of triangle PAB

= 2* (r cos(60) * r sin(60) /2)

= 2* ((r/2) * r (sqrt(3)/2) /2)

= sqrt(3) * r^2 / 4

= r^2 * sqrt(3)/4

Area of segment AOB

= area of segment PAOB - area of triangle PAB

= r^2 * ( pi/3 - sqrt(3)/4 )

By symmetry, area of shaded area

= area of segment AOB  -  area of triangle AOB

= area of segment AOB  -  area of triangle PAB

= r^2 * ( pi/3 - sqrt(3)/4 )  -   r^2 * ( sqrt(3)/4)

= r^2 * ( pi/3 - 2*sqrt(3)/4 )

= r^2 * ( pi/3 - sqrt(3)/2 )

Since r = b, we substitute

Shaded area

= b^2 * ( pi/3 - sqrt(3)/2 )

Substitute b=6

area

= 6^2 * ( pi/3 - sqrt(3)/2 )

= 6.522197 square units

Ver imagen mathmate