Answer:
Option B.
Step-by-step explanation:
Scale factor of the image = [tex]\frac{\text{One side of the triangle FED}}{\text{Corresponding side of the triangleABC}}[/tex]
= [tex]\frac{\text{DF}}{\text{AC}}[/tex]
= [tex]\frac{3}{6}[/tex]
= [tex]\frac{1}{2}[/tex]
Coordinates of point C → (-2, 2)
Coordinates of the corresponding point C' after dilation with a scale factor [tex]\frac{1}{2}[/tex],
C(-2, 2) → C'(-1, 1)
Coordinates of point C' after reflection across y-axis,
C'(-1, 1) → C"(1, 1)
Followed by the translation of 2 units downwards,
C"(1, 1) → D[1, (1 - 2)]
→ D(1, -1)
From the graph we get the same coordinates of point D as (1, -1).
Therefore, ΔABC was dilated by a scale factor of [tex]\frac{1}{2}[/tex], reflected across the y-axis and moved through the translation of 2 units downwards.
