In △ABC, AB = BC = 20 and DE ≈ 9.28. Approximate BD.
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Answer:
BD = 5
Step-by-step explanation:
∠A = 60°
Since AB = 20 = BC, Then ∠B = 60° resulting in a equilateral triangle with ∠C = 60°. Then dividing ∠DAE into half gives 4 = angles of 15° yielding each secition of BC being equal to 20/4 = 5. Do i don't think DE ≈ 9.28 cannot occur.