shylizard47
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Which complex number from the table multiplied with B from the table will result in the product 159 + 27i?
A -3 − 4i
B -7 − 6i
C 13 + i
D -9 + 6i
E 8 − 8i
F -15 + 9i
G 2 + 12i
H 6 − 10i

Respuesta :

olayemiolakunle65

Answer:

F. -15 + 9i

Step-by-step explanation:

B = (-7 -6i)

Multiply B by F = (-15 + 9i), would give;

B × F = (-7 -6i) × (-15 + 9i)

        = -7 (-15 + 9i) - 6i (-15 + 9i)

       = 105 -63i + 90i - 54([tex]i^{2}[/tex])

But [tex]i^{2}[/tex] = -1, so that:

105 -63i + 90i -54([tex]i^{2}[/tex]) = 105 -63i + 90i -54(-1)

                                  = = 105 -63i + 90i + 54

          = 159 + 27i

B × F = 159 + 27i

Thus the required complex number is F (-15 + 9i).

Answer:

Multiplying F with B results in the complex expression 159 + 27i:

(B)(F)

=  

(-7 − 6i)(-15 + 9i)

 

=  

105 − 63i + 90i − 54i2 (Apply the FOIL method.)

 

=  

105 + 27i − 54(-1) (i2 = -1)

 

=  

105 + 27i + 54

=  159 + 27i

Step-by-step explanation:

Plato answer

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