AD=DB and AE =EC
M
EF= 6
M
I0pts
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Answer:
32 deg
Step-by-step explanation:
AD = DB and AE = EC
Then segment DE is parallel to segment BC by a theorem.
Angles AED and ECF are corresponding angles of parallel lines cut by a transversal, so they are congruent.
m<ECF = m<AED = 32 deg