How many sulfur atoms are generated when 9.42 moles of H2S react according to the following equation: 2H2S+SO2→3S+2H2O
A) 8.51 × 10^24
B) 3.78 × 10^24
C) 8.51 × 10^23
D) 9.42 × 10^23

Respuesta :

znk

Answer:

A) 8.51 × 10²⁴  

Explanation:

1. Gather all the information

            2H₂S + SO₂ ⟶ 3S + 2H₂O

n/mol:   9.42

2. Calculate the moles of S atoms

The molar ratio is 3 mol S:2 mol H₂S

[tex]\text{Moles of S} = \text{9.42 mol H$_{2}$S} \times \dfrac{\text{3 mol S }}{\text{2 mol H$_{2}$S }} = \text{14.13 mol S}[/tex]

3. Calculate the atoms of S

[tex]\text{Atoms of S } = \text{14.13 mol S} \times \dfrac{6.022 \times 10^{23}\text{ S atoms}}{\text{1 mol S}} = \mathbf{8.51 \times 10^{24}}\textbf{ S atoms}[/tex]

 

The sulfur atoms that should be generated is [tex]A) 8.51 \times 10^24[/tex].

Given that,

  • 9.42 moles of H2S reacted to the given equation.
  • Also, 1 mole for the substance contains [tex]6.022 \times 10^23[/tex] no of atoms & molecules.

  • The calculation is as follows:

[tex]= \frac{3\times 6.022\times 10^23\times 0.42}{2}\\\\= 85.0909 \times 10^23\\\\= 8.509 \times 10^24\\\\= 8.51 \times 10^24[/tex]

Therefore we can conclude that the sulfur atoms that should be generated is [tex]A) 8.51 \times 10^24[/tex].

Learn more: brainly.com/question/17127206