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The roots of $x^2+8x+4$ are the same as the roots of $Ax^2+Bx+1$. What is $A+B$?[tex]The roots of $x^2+8x+4$ are the same as the roots of $Ax^2+Bx+1$. What is $A+B$?[/tex]

Respuesta :

Alfpfeu

Answer:

4.5

Step-by-step explanation:

Hello, please consider the following.

First of all, let's assume that A is different from 0.

[tex]x^2+8x+4\\\\\text{It means that the sum of the zeroes is -8 and the product is 4}\\\\Ax^2+Bx+1=A(x^2+\dfrac{B}{A}x+\dfrac{1}{A})\\\\\text{So the sum of the zeroes is } -\dfrac{B}{A} \text{ and the product is }\dfrac{1}{A}\\\\\text{It comes.}\\\\-\dfrac{B}{A}=-8 <=> \dfrac{B}{A}=8\\\\\dfrac{1}{A}=4[/tex]

So,

[tex]A=\dfrac{1}{4}\\\\B=\dfrac{8}{4}=2\\\\A+B=\dfrac{1+8}{2}=\dfrac{9}{2}=4.5[/tex]

Thank you.

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