PLEASE HELP the vertex form of the equation of a parabola is y = (x - 3)2 + 36. what is the standard form of the equation?
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Answer:
[tex]\large \boxed{\sf \bf \ \ x^2-6x+45 \ \ }[/tex]
Step-by-step explanation:
Hello, please consider the following.
You need to develop the expression.
[tex]y=(x-3)^2+36\\\\=x^2-2 * 3 * x +3^2+36\\\\=x^2-6x+9+36\\\\=x^2-6x+45[/tex]
Thank you.